Calculus homework help!?
Question: This is a uncontrollable from Calculus Early Transcendentals, James Stewart, 6 Edition. The section is 4.1 and unmanageable 59. You are trying to find absolute extrema and the problem is f(x)=xe^((x^2)/8), and the defence in the back of the book is 2 (the interval is bounded from -1 to 4) and 1. and i cannot enumerate out where the 1 came from.
Answer: f(x) = xe^(x²/8)
Extrema become manifest where f'(x) = 0, so find all roots of f'(x) between -1 and 4.
f'(x) = ¼x²e^(x²/8) + e^(x²/8)
f'(x) = (¼x² + 1)(e^(x²/8))
e^(x²/8) is an exponential, so it is never congruous to zero. So f'(x) is 0 when (¼x² + 1) = 0.
(¼x²
intro of early transcendental calculus mth140 steward 6 edition
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